Drupal 7 How to get rendered blocks in content region (for example)

I did something like this:

// delta now is a String, the id of the block, not a number.
$block = module_invoke('module', 'block_view', 'delta');    
$rendered_block = theme('block', $block);

Hi,
First I would highly recommend you get a copy of the "Examples for Developers" located here: http://drupal.org/project/examples. The "render example" is loaded with great information.

I took look at the Drupal 7 block.module listing and came up with this:

function print_block_test($region = 'sidebar_first', $block_id = 58) {

  $renderable_block = t('Block Not Found');
  $output = '';
  
  $block_list = block_list($region);

  foreach($block_list as $block) {
   if ($block->bid == $block_id) {
      $renderable_block=  _block_get_renderable_array(array($block));
      $output = drupal_render($renderable_block);
      break;
   }
  }

  return $output;
}

So, in my example you need to supply the region name and then the bid (block id field located in the block database table). The documentation for hook_page_alter() http://api.drupal.org/api/drupal/modules--system--system.api.php/functio... describes the default Drupal 7 region names.

The "render example" ( "Examples for Developers") demonstrates how you can iterate through the regions of a given page.

Note! Since this method was intended for educational purposes only, I looked at one of my development installations. 58 happens to be the block id (bid) for the "Search" block. It's for demonstration purposes only. :) So in other words, look at your own installation and determine the block id (bid) for whatever block you are trying to render.

Sample use: You can call the above function as a menu callback (hook_menu()). The block found is rendered in the content region.

I hope that helps.

Yea i had a bit of a head scratch over this one.... module_invoke is one of those indispensable drupal functions.

The drupal 6 method below applied to the webform module block:

<?php 
         $block =  module_invoke('webform', 'block', 'view', 'client-block-11'); 
         print $block['content']; 
  ?>

The answer is directly under are noses as it turns out, everything in drupal 7 is now stored to the last point in a render array, and therefore you just have to render out the array...

<?php
          $block = module_invoke('webform', 'block_view', 'client-block-11');
          print render($block); 
?>

You can obtain the block information by going to 'Administer -> Site building -> blocks' for drupal 6 or 'structure -> blocks' for drupal 7 and hit 'configure' next to the block to check its url.

drupal 7 url for block = admin/structure/block/manage/webform/client-block-11/configure
drupal 6 url to block = admin/build/block/configure/webform/client-block-11

Needless to say, but for the new.. don't forget to have the 'text format' on 'php code' when implementing the php code in your node. This can be turned on in the module page.

hope this helps.

None of the above approaches completely worked for me. Here's mine:

/**
 * Get a block suitable for rendering.
 * Note: the block does not have to be enabled in $region.
 * @see includes/block.module/_block_render_blocks()
 * @see includes/block.module/_block_get_renderable_array()
 */
function siteoverride_embed_block($module, $delta, $region='content') {
  // Create block stub.
  $block = new stdClass();
  $block->module = $module;
  $block->delta = $delta;
  $block->region = $region;
  // Load title.
  global $theme_key;
  drupal_theme_initialize();
  $block1 = db_query("SELECT title FROM {block} WHERE module = :module AND delta = :delta AND theme = :theme",
                    array(':module' => $module, ':delta' => $delta, ':theme' => $theme_key))->fetchObject();
  if (is_object($block1) && isset($block1->title)) {
    $block->title = $block1->title;
  }
  // Render the content and subject for the block.
  $blocks = _block_render_blocks(array($block));
  // Get an array of blocks suitable for drupal_render().
  $array = _block_get_renderable_array($blocks);
  return $array;
}

Then, if your module is 'block' and delta is '1', write in your template file:

print render(siteoverride_embed_block('block', '1'));

I found this

$block = block_load('block', '1');
$output = drupal_render(_block_get_renderable_array(_block_render_blocks(array($block))));
print $output;

(here: http://api.drupal.org/api/drupal/includes--module.inc/function/module_in...)
This only works form me...

Unfortunately - I've tried all mentioned here but I almost always get the following error:

Notice: Trying to get property of non-object in function block_block_view() (line: 245 in file /users/zalohovane/zusorchidea.com/test/modules/block/block.module).


T

Hi,

As I said I have 2 separate things one is a view and other one is block. I just want to wrap them up and display them together. Any idea how can I accomplish that?

I started with one block inside another block using all of the techniques of using module_invoke but not able to get it working.

Please help.

Thanks in advance.
Rahul

I couldn't get the code here to work for me, I suspect that I just couldn't find the right parameters. So, my solution, which I am sure someone more knowledgeable will explain to me why you shouldn't do this, is to place the block into a clean region and copy the HTML from the generated 'view source' of the webpage and place that into the div I want in content. Seems to work????

Rohan

I am relatively new to Drupal, and have spent several hours figuring out how to do this as there was no one place it was all documented.

givens:
Drupal 7.23
You wish to display a view in your content.
modules>core>php filter is enabled and permissions are set to allow you to inject php code into your content.
You have created your block and view

To locate the name of the block to be displayed
Structure>Blocks
Find your block in the list and click on the configure option
Then in your browsers address bar you will see something like the following:
YourDomain.tld/content/town#overlay=admin/structure/block/manage/views/intownshow-block/configure

The information between '/views/' and '/configure' is the name of your view or it's delta (I believe that is the correct term) or in this case 'intownshow-block'.

Now go to the content you wish to place the block in and edit it using the “PHP Code” in the text format dropdown.

Insert the following were you wish your block to appear in your content:

<?php

$block = block_load('views', 'intownshow-block');
print drupal_render(_block_get_renderable_array(_block_render_blocks(array($block))));

?>

Note there is a space between 'print' and 'drupal_render...' in the above

Then save the edited content and view it should work.

There is a (more) up-to-date documentation for embedding block content to any template.

Placing the contents of a block in any location
https://www.drupal.org/node/26502

module_invoke didn't work for me and I had to use block_load but where delta is the machine name and not the block id. 

$my_block = block_load('my_module_name', 'delta');
$block_for_display = drupal_render(_block_get_renderable_array(_block_render_blocks(array($my_block))));

Within my_module, I had hook_block_view and another function prepare the block content for rendering as shown in this example:
https://api.drupal.org/api/examples/block_example!block_example.module/7...

function my_module_block_view($delta ='') {
    $block = '';
    switch ($delta) {
        case 'blockA':
            $block['content'] = my_module_contents($delta);
            break;
    }
    return $block;
}

function my_module_contents($which_block) {
    switch ($which_block) {
        case 'blockA':
            $content = array(
                '#markup' => variable_get('some_field'),
            );
            return $content;
    }
}