Closed (fixed)
Project:
Views (for Drupal 7)
Version:
6.x-2.12
Component:
Views Data
Priority:
Major
Category:
Support request
Assigned:
Unassigned
Issue tags:
Reporter:
Created:
1 Mar 2011 at 20:49 UTC
Updated:
26 Nov 2011 at 13:01 UTC
Hi,
I have a view to show a few fields of a job-node (module: job-search) in a table. And on that table I want to add a field »Apply for this job«.
So I added the field »Job Node ID« and used for the link-path (Output this field as a link) the prescribed substitution pattern [nid_1].
But this pattern produces for every node only a ”0”:
Link-Path is: job/apply/[nid_1] and the result is job/apply/0.
Please help.
Comments
Comment #1
dawehnerIt perhaps would be worth to provide an export.
In general if this bug is specific to the job_search module you should better move the issue against the job_search module as you can read on http://drupal.org/node/571990
Comment #2
quixxel commentedHi,
thanks for your quick response.
you can find the export of that view here: http://media.cae-forum.de/views_export_jobs
And thanks for your helpfull advice,
but I don't know if that behaviour is a bug.
Maybe someone else can give me an advise?
Comment #3
R.Hendel commentedHi,
If this is an active issue please repost it at Sob-Search issue queue
I will fix this to clean queue.