First of all, sorry if the solution is somewhere ... I really search during 3 days ... sorry also: I am a newbie in drupal and php.
Because I am not sure the solution I have in mind is the best: let first describe what I want.
Goal
I am a scientist and I proposed to make a new web page for my lab. I want first to create the page people. They are different kinds of 'members' : 'labhead', 'researcher', etc. At the end, I want a web page containing a list like this:
<h4>Laboratory Head</h4>
Picture - Name - email - etc. (for the first lab head)
<h4>Research Scientist</h4>
Picture - Name - email - etc. (for the first scientist)
Picture - Name - email - etc. (for the second scientist)
<h4>PhD Students</h4>
Picture - Name - email - etc. (for the first phd student)
...
Solution Proposed
To have a nice custom view, I updated the method "phptemplate_views_view_list_memberview" in the file template.php (which I created). I followed the very nice instructions given by Dale McGladdery : http://groups.drupal.org/node/2647.
By following the method in the above link, I can create a nice custom view with ALL the members of the lab having. The problem is to separate them according to their categories.
Problem
I would like to modify the method "phptemplate_views_view_list_memberview" according to:
<?php
function phptemplate_views_view_list_memberview($view, $nodes, $type) {
$output = '<h2>Laboratory Head</h2>';
$output .= '<br><TABLE ALIGN="center" cellpadding="10" cellspacing="10">';
$output .= _add_persons_in_position($view, $nodes,'labhead');
$output .= '</TABLE>';
$output .= '<h2>Research Scientist</h2>';
$output .='<br><TABLE ALIGN="center" cellpadding="10" cellspacing="10">';
$output .= _add_persons_in_position($view, $nodes,'scientist');
$output .='</TABLE>';
return $output;
}
function _add_persons_in_position($view, $nodes,$postype) {
....
}
the problem is to compare the category of each node and to print it only if it matches the desired $postype.
Thank you for any suggestions (or any turnaround)
colin