embed views doesn't get refreshed

If i print_r($form) i can see that the form has the views_refresh array itens:

[#ajax] => Array
(
[enabled] => 1
[disable_redirect] => 1
[remove_form] =>
[scroller] =>
[views_refresh] => 1
[views_refresh_enabled] => Array
(
[comentarios] => comentarios
[comentarios:block_1] => comentarios:block_1
)

)

so far i couldn't tell what's avoind the view refresh.

any help?

i resolved this manually, but with this module i couldn't.
more info here:
http://drupal.org/node/1246672

sorry, i did my own ajax call...
See http://drupal.org/node/1246672#comment-4856824 then i added :
$('#mycontainer).html(data.display);
Drupal.attachBehaviors($('#mycontainer'));

ok, i'm pasting here, as a reference. From august (when i posted it here) to today, many things changed.

You'll need to create a JS plugin, adding a custom.js to your theme:

$(document).ready(function(){
	//see reference
	//http://drupal.org/node/463258
	//Available Hooks: init, submit, redirect, message, afterMessage, scrollFind, complete
	Drupal.Ajax.plugins.RemoveLoader = function(hook,args) {
		//alert(hook);
		//args cames from the form
		//it's useful to use the plugin jQuery Dump
        if(hook === 'submit') {
			//a comment was submitted
			$("#comment-form").append('<p class="ajax-loading">&nbsp;</p>');
			//$('#edit-submit').attr('disabled', 'disabled');
        }
		if(hook === 'redirect') {
               //do whatever you want after form has been submitted
			   $("#comment-form").find('p.ajax-loading').hide();
			   // get the ajax page by firebug console, contruct it by json and send it in your tpl
			   $.ajax({
				  type: 'get',
				  url: $("#AjaxURL").val(), 
				  success: function(data){
						$('#block-views-comentarios-block_1').find('div.content').html(data.display);
						Drupal.attachBehaviors($('#block-views-comentarios-block_1').find('div.content'));
						//$('#block-views-comentarios-block_1').find('ul.pager > li > a').
						//see / ajax.jsDrupal.behaviors.ViewsAjaxLinks					
						
				  },
				  dataType: 'json', //define the type of data that is going to get back from the server
				  data: 'js=1' //Pass a key/value pair
				});
				return false;		 
        }
        if(hook === 'afterMessage') {
				//if a error occurs
               //do whatever you want after message is displayed,
				$("#comment-form").find('p.ajax-loading').hide();
        }
	};
});

My tpl has an input hidden with the ajax full url, i'm using i18n:

($language->prefix == "en") ? $langView = $base_path . 'en/': $langView = $base_path ;
$urlhidden = $langView.'views/ajax?js=1&page=0&view_name=my_view_name&view_display_id=block_1&view_args='.$my_arg.'&view_path='.$_GET['q'].'&view_base_path=null&view_dom_id=4&pager_element=0';
 echo '<input id="AjaxURL" type="hidden" value="'.$urlhidden.'" />';
print $comment_region; // i added the views block to a region on my theme

But at the beginning i was using a preprocess function to add the view to my tpl, in template.php

function phptemplate_preprocess_page(&$vars) { 	
 $myview = views_get_view('my_view');
 $myview->set_arguments(array($myarg));
 $myview->override_path = 'current_path';
 $vars['comment_region'] = $myview->preview();
}