Block visible for specific nodes/terms and their children
I really wanted to create multiple image galleries and for each gallery have a different menu. It was also necessary to display this menu for all child galleries and images. I didn't particularly feel like adding each node to the pages box on the configure menu block screen, as the number of images and galleries would be growing all the time. I decided that I needed block inheritance, so I created my own includes file to contain functions to do this for me. It's a bit messy and may not suit everyone's taxonomy structure, but it meets my needs.
Steps
1. Set up your menu / block.
2. Set the "page specific visibility settings" to be "Show if the following PHP code returns TRUE" on the block configuration screen.
3. In the "Pages" field, put something similar to the following:
<?php
include_once "./includes/inherit_blocks.inc";
if (check_path("node/1")) return TRUE;
return inherit_display_block(123);
?>The first line just includes the file containing the functions. The check_path() function is for those nodes that you just want to hardcode the paths for, while the last line calls the function which handles the inheritance for tid 123.
4. Create the inherit_blocks.inc file and add the following:
<?php
function inherit_display_block($tid = 0) {
$is_child = FALSE;
if ($tid != 0) {
$this_page = drupal_get_path_alias($_GET['q']);
$url_parts = split("/", $this_page);
$num_parts = count($url_parts);
if ($url_parts[$num_parts-2] == "tid") {
$this_tid = $url_parts[$num_parts-1];
if ($this_tid == $tid) return TRUE;
$is_child = get_child_tids($tid, $this_tid);
} elseif ($url_parts[$num_parts-2] == "node") {
$this_node = $url_parts[$num_parts-1];
$is_child = check_child_node($tid, $this_node);
}
}
return $is_child;
}
function get_child_tids($parent, $tid) {
$child = false;
$result = db_query("select tid from term_hierarchy where parent=$parent");
while ($child_tid = db_fetch_object($result)) {
if ($tid == $child_tid->tid) return true;
$child = get_child_tids($child_tid->tid, $tid);
if ($child) return true;
}
return false;
}
function check_child_node($parent, $node) {
$child = false;
$result = db_query("select tid from term_node where nid=$node");
while ($node_tid = db_fetch_object($result)) {
$tid = $node_tid->tid;
$result2 = db_query("select tid from term_hierarchy where parent=$parent");
while ($child_tid = db_fetch_object($result2)) {
if ($tid == $child_tid->tid) return true;
$child = get_child_tids($child_tid->tid, $tid);
if (!$child) return true;
}
}
return false;
}
function check_path($path) {
$this_path = drupal_get_path_alias($_GET['q']);
$regexp = '/^'. preg_replace(
array('/(\r\n?|\n)/', '/\\\\\*/', '/(^|\|)\\\\<front\\\\>($|\|)/'),
array('|', '.*', '\1'. preg_quote(variable_get('site_frontpage', 'node'),
'/') .'\2'), preg_quote("$path", '/')) .'$/';
return preg_match($regexp, $this_path);
}
?>
PHP HELP block on single node?????
Hey all,
I am completely useless when it comes to PHP and new to Drupal, and have spent hours trawling the forum for something like this. I basically need a simple PHP script to show a block on a node when using the "Show if the following PHP code returns TRUE" option on a block. the URL is /Pictures and the node is number 9. Someone please give me hand with this, there must be a simple way?
Sam
www.solarfly.com - Under construction and still learning Drupal
Sam, just put node/9 in the
Sam, just put node/9 in the "display only on these pages" box.
Meanwhile, for those who want to display a block only on pages which are tagged with a particular taxonomy term, here is a script you can use in D5 and an update for D6:
http://drupal.org/node/507540
You need to look up the term IDs for the terms you want to filter on, and enter them in the first line of this script (inside the "myterms" array). I go to the taxonomy admin, list terms from the vocabulary I want to use, and then roll my mouse over the edit link for the term I want. That shows the term and vocabulary IDs in the status line of the browser.