Why is there no "is all of" operator for select list filters?

In Drupal 6 are possible, but not in Drupal 7!?

keep calm ...

So you assigned the issue to yourself, so let's see whether you can find a patch for that.

This is JUST an experimental patch, please don't blame me if it does not work, but sure feedback would be cool.

I tested the patch with Views 7.x-3.3 and Better Exposed Filters 7.x-3.0-beta1. As master for Viewfield 7.x-2.x-dev and as a page with filters in the block. In addition, several filters were combined. So far everything works very well.

Testbot?

Wrong version for the bot.

ah ha. How did I not spot that! :)

Reupload the patch for the bot ...

I have just tested, seems to work fine.

Thanks! Committed to both 7.x-3.x and 8.x-3.x

This change breaks filter OR grouping. The join for optional field values changes from LEFT JOIN to INNER JOIN, making the field value required (effectively ANDing the filter group). See #1766338: Incorrect filter group OR behavior, LEFT JOIN changed to INNER JOIN.

I'm re-opening this issue and unassigning @buntstich. See #1766338: Incorrect filter group OR behavior, LEFT JOIN changed to INNER JOIN.

@dawehner, there is a patch in that issue that simply reverts the commit from this one, but applying that will result in a missing operator error for anyone using the new operator.

I guess the best option is to fix this issue so the new operator works without breaking filter OR groups, but doing so is probably beyond my ability/time at present.

I'm unable to get the desired result using 'is all of' as this patch is meant to fix in D7.

I have a taxonomy group,
Banana
Apple
Orange

I have a node that is assigned both Banana and Orange.

In my view I have an exposed filter set against the taxonomy terms using 'is all of' as I want users to be able to filter down to an exact match.

So if I expose filter Banana only I get the node.

If I expose filter Orange only I get the node.

However if I expose filter Banana AND Orange I get nothing.

Any thoughts as to why?

I can obviously use 'is one of' that that gives a very loose criteria and any node with Banana or Orange will be displayed, but that's not the required result.