By andersin88 on

How to show specific block in node that under taxonomy/term/6 ?

Page specific visibility settings
taxonomy/term/6* //this for showing block on website.com/taxonomy/term/6

what path should i add in page specific visibility settings to show block on all node that under taxonomy/term/6

is that need add php snippet?
http://drupal.org/node/115419

⋅ Categories: Drupal 6.x

Comments

nevets’s picture

nevets commented

taxonomy/term/6 only covers that page, not node pages where the node has term id 6.

The snippet is for controlling visibility based on node type and/or id.

I would suggest using the context module, with it you can set up a reaction on taxonomy term(s) and have it show select blocks in the region(s) of your choice.

sadashiv’s picture

sadashiv commented

Yes you can use the php snippet to filter the visibility. Just you will need to add the following code

if(arg(0) == 'node' && is_numeric(arg(1))){
    $nid = arg(1);
    $node = node_load(array('nid'=>$nid));
    $terms = taxonomy_node_get_terms($node);
    foreach($terms as $term){
        if($term->tid== 6)   //6 is the term id I am passing hardcoded
            return true;
   }
    return false;
}
else
return false;

Hth,
Sadashiv.

andersin88’s picture

andersin88 commented

thank, it work.

stinky’s picture

stinky commented

Do you know how to get this working in Drupal 7?
I'm trying to display a block based on a taxonomy term. I can get it working in Drupal 6 but not 7.

sadashiv’s picture

sadashiv commented

I think 

if(arg(0) == 'node' && is_numeric(arg(1))){
    $nid = arg(1);
    $node = node_load(array('nid'=>$nid));
    $terms = field_view_field('node', $node, 'field_tags', array('default'));
    $terms = $terms['#object']->field_tags['und'];

    foreach($terms as $term){
        if($term['taxonomy_term']->tid== 6)   //6 is the term id I am passing hardcoded
            return TRUE;
    }
    return FALSE;
}
else {
    return FALSE;
}

should work, not tried.