By eaposztrof on

hi..
have a content of review type . which have an field_banner field, with content:

<?php $node->field_banner (array)

    $node->field_banner[0] (array)

        $node->field_banner[0]['value'] **
            banner code! 
        $node->field_banner[0]['format']
            1 
        $node->field_banner[0]['view']
            <p>banner code!</p> ?>

i want to put show the $node->field_banner[0]['view'] in the $banner block

⋅ Categories: Drupal 5.x

Comments

eaposztrof’s picture

eaposztrof
Primary language Hungarian
Location Székelyföld
commented

oh, sorry.. i press the post button before finished..
so..

i want to put the $node->field_banner[0]['view'] in the $banner block,
i configured the block:
content: 

<?php
print $node->title;
print print_r($node->content['field_banner']);
?>

Show on only the listed pages: review/*

and just "1" printed..

how i can doo that? thx..

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nevets’s picture

nevets commented

Create a custom block and PHP code something like

<?php
if ( arg(0) == 'node' && is_numeric(arg(1)) ) {
  $node = node_load(arg(1));
  if ( node->type == 'review' ) {
    $node = node_build_content($node, FALSE, TRUE);
    print $node->field_banner[0]['view'] ;
  }
}
?>

Make sure you set the input format to 'PHP Code' and save the block.

Then assign the new block to the approriate region.

eaposztrof’s picture

eaposztrof
Primary language Hungarian
Location Székelyföld
commented

its working great..

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