I have a custom node type I created with CCK that uses image field. I have teaser and node views set up with a custom content template. Both of these views are working correctly.
I recently created a new block view, set the view type to list and added the image field to the Fields list. I used the Theme Wizard, added a function to my theme template.php file, and created a views-list-[viewname].tpl.php file.
Within the tpl.php file I have a line of code: <?php print $field_image_fid; ?>
which returns something like <img src="path_to_image" />
I'm trying to create a link around this image and am banging my head against a wall. I'd like to get the path to the image and the image file name and have calling:
$node->field_image[0]['filename']
...but this returns nothing. I've tried print_r($node) and there's nothing I want in the array. I'm probably being stoopid but for the life of me I cant remember/figure out how to access the "real" array of node info from within this block. I call $node->field_image in my teaser and body templates just fine...
Any suggestions? Thanks,
pp
[Edited to add <code> and </code> tags; nevets]
Comments
Using image field
Using image field 5.x-2.0-rc6, image cache 5.x-2.0-beta and views 5.x-1.6 when I add an image field to views (as a field) under options I have a drop down that for each image cache type allows me to show the image as an unlinked image, image linked to node or image linked to full size image.
Yep--I have my image field
Yep--I have my image field set up correctly: I already have a teaser and body views templates. What I'm trying to do is access the image field values within a custom list view.
For example: the object "$field_image_fid" provided by the Theme Wizard outputs something like:
img src="path_to_file"...
What I want is to call something like:
$node->field_image[0]['filename'] within my views-list.tpl.php file that will output the string value of the image name....
OT: Code tags
Thanks for adding those nevets. I realized after I posted that I forgot them and couldn't edit my original post.
Same issue
I have the same issue, have you had any luck? The filename is populated for me, but still returns blank when queried...
All the best,
Steve V
A solution
I used Contemplate as a method of getting to the relevant field names and PHP code.
print $field_photo_filepathshould be
print "<img src='/" . $node->field_photo[0]['filepath'] . "'</img>"All the best,
Steve V
Having the same issue.
Having the same issue. Desperate to get to the img path inside $field_image_fid.
Tried devink's solution, with Contemplate, but still no joy.
Figured it out...
1) In your file, use...
print "<pre>"; print_r($node); print "</pre>";...to get a list of the incoming fields, then...
2) You can use something like...
print "<strong>File Name:</strong> ".$node->node_data_field_image_field_image_alt;...to grab the file name.
HTH,
Sean
Thanks for the reply. I've
Thanks for the reply. I've tried all these things but they don't work inside a block view. Doing:
print_r($node);inside my block view returns:
stdClass Object ( [nid] => 57 [random_sort] => 0.000761895441228426 [node_data_field_image_field_image_fid] => 35 [node_data_field_image_field_image_title] => [node_data_field_image_field_image_alt] => [files_filename] => [files_filepath] => )As you can see there are no values for any of the array elements that you'd think would give me what I want. OTHO, the block view does return the node ID, but I havent figured out how to return all the properties for a give node ID.
Any tips?
Thanks again
Subscribing...
I too have this issue
I am trying to customise a view to have a cck imagefield image open in a new browser window.
here is the contents of my views-list-viewname.tpl.php at present
and the
<?php print_r($node) ?>output isAs you can see I dont even have the filepath property in my array at all.
using Imagefield 5.x-1.2-rc1
Subscribing to this issue with fingers crossed :)