By netron on

i have a block which has
"show if the following PHP code returns TRUE" selected, with this code:

<?
global $node;
if ($node->type=="page")
{
return TRUE;
}
?>

and yet when i visit a page node, the block isnt displayed. is the syntax of the code above correct for Drupal 6.x?

⋅ Categories: Drupal 6.x

Comments

netron’s picture

netron commented

found the answer here:
http://drupal.org/node/64135

"Show block only for specific content type" example.

teyser’s picture

teyser commented

Hi,
Go to block configure page,
In block specific settings...

Write the PHP code and the select the PHP code on select box

For ex this site url http://localhost/drupal/

If(arg(0)==drupal)
return true;
else
return false;

It's working fine..

Thanks,
Raj