By msteudel on

I am using Drupal 5.x and have installed the usernode. I then created a view based off of their default userlist.

I am editing the userlist in my template.php with the following function:

function theme_views_view_userlist( $view, $type, $nodes, $level = NULL, $args = NULL ) {
$html = '

    ';
    if( is_array( $nodes ) && count( $nodes ) > 0 ) {

    foreach( $nodes as $nid ) {
    $user = node_load( $nid->nid );
    $html .= '

  • ' . $user->user->profile_first_name . ' ' . $user->user->profile_last_name . '

    • ';
    }
    }
    $html .= '

';

return $html;
}

Which is working fine. But I'm trying to figure out how to display the exposed filter for this .... any direction would be appreciated

Thanks

⋅ Categories: Drupal 5.x

Comments

msteudel’s picture

msteudel commented

Sorry forgot to add the code tags:

function cfgg_views_view_userlist(  $view, $type, $nodes, $level = NULL, $args = NULL ) {
	
	$html = '<ul>';
	if( is_array( $nodes ) && count( $nodes ) > 0 ) {
		
		foreach( $nodes as $nid ) {
			$user = node_load( $nid->nid );
			$html .= '<li>' . $user->user->profile_first_name . ' ' . $user->user->profile_last_name . '</li>';
		}
	}
	$html .= '</ul>';
	
	return $html;
}
msteudel’s picture

msteudel commented

Bump ... Sorry hoping someone may have an answer

skru09’s picture

skru09 commented

Hi

I am trying to get the exposed filter value as well. Were you successful in getting it??
Any kind of guidance would be appreciated.

Thanks