By CLamont on
Writing a text filter... something like Textile only streamline and simpler. About done with the filter proper, but trying to streamline the code.
I wrote this to set font size on the fly:
function _myfilter_filter_fontsize($chr, &$text) // If chr match here...
{
if (strstr($text, $chr)) // Three X as fast with this.
{
$text = preg_replace('/
'.$chr.'([0-7]) # Token and any digit from 0 to 7,
(.+) # 1 or more characters followed
'.$chr.'{1} # by one token
[0-7]{0,1} # and an optional digit.
/x', "<font size=\"$1\">$2</font>", $text);
$text = str_replace("$chr$chr", // Double chr escapes.
$chr, $text);
}
}
If I'm using a ~ as my flag, the syntax would be:
The font is normal ~3THEN BIGGER~ then returns back to normal when I type another ~ OR a ~ and some numeral.
What I'd like to know is how to make the second numeral THE SAME numeral as the first. In other words, is there a syntax for the regex string that allows me to specify the $1 variable as I did in the replacement string?
Curtis
Comments
backreference
syntax is
\\1or \1 depending on whether " or ' used.--
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Drupal development: making the world better, one patch at a time. | A bedroom without a teddy is like a face without a smile.
That did the trick...
That did the trick... thanks a lot. Saved me more hours of slogging through manuals, I'm sure.
Curtis