[Solved] Views, argument and PHP custom code : what am I missing?

By mdupont on 26 Jun 2009 at 15:52 UTC

Hi,

I have a view that returns a list of node titles of a particular content type. I'm displaying this view in a block. Now, I want to filter the results depending on the taxonomy terms of the node my block is displayed on.
Let's say my taxonomy is the following:
- Vocabulary 1 : foo
-- Term 1 : fbar
-- Term 2 : foob
- Vocabulary 2 : bar
-- Term 1 : misc
-- Term 2 : baz

When I'm visiting a node, I want to display a block in the sidebar, containing items that have one or more terms in common, but only if these terms are belonging to Vocabulary 2. So in my view parameters I've added Taxonomy: term ID as an argument, and used the following PHP snippet to provide the default argument :

$node=node_load(arg(1));
if($node->taxonomy){
  foreach($node->taxonomy as $term){
    if ($term->vid == 2) // vid of my vocabulary
     {$terms[]=$term->tid;
    } else {return;}
}
if ($terms) {return implode('+',$terms);} else {return;}
}else {return;}

This code works if the node we are visiting has only taxonomy terms from Vocabulary 2. If the node has taxonomy terms from Vocabulary 1 and Vocabulary 2, the validation fails and the results are not filtered ; I don't understand why. Am I missing something?

Thanks !

Comments

return null

binford2k commented 26 June 2009 at 16:06

As soon as you hit $term->vid != 2 your snippet returns nothing.

Just remove the else clause from the foreach loop. It's not needed. As a matter of fact, none of them are:

$node=node_load(arg(1));
if($node->taxonomy){
  foreach($node->taxonomy as $term){
    if ($term->vid == 2) {
      $terms[]=$term->tid;
    }
  }
}
if ($terms) { return implode('+',$terms); }