By savioret on

I was wondering if there is any way to decide to show a block from code, but inside a module code.
I've seen that there's an option (from admin pages) to add code to decide if a block must be shown, but I need to decide this from my module because the decision is a bit complex and I need to check it inside some hooks...

Any help would be appreciated.

⋅ Categories: Drupal 6.x

Comments

ludo1960’s picture

ludo1960 commented 
<?php
$block = module_invoke('theblockyouwanttouse', 'block', 'view', '0');
print $block['content']
?>
savioret’s picture

savioret commented

Thanks ludo,

But what I dont understand, is that if I make a print I'll show the block content inside the page content...
How do I show it in its right place?

ludo1960’s picture

ludo1960 commented

..is the right place?

savioret’s picture

savioret commented

The place where the block has been setup for. For example in my case I setup the block to be shown in the left side, in the upper position.
Where should I use the print to show the block exactly in the region where it was configured to be ?

I think another solution could be setting a block to be *always* shown, and return nothing in hook_block when I don't want it to be shown. But this always generates a hook call for every page load.

ludo1960’s picture

ludo1960 commented

Why not place the code in the page.tpl, you can use a php if() clause to test for your condition?

savioret’s picture

savioret commented

Hmmm... that's the same situation as setting the code from the admin pages. The problem is that I need to show the block when certain hook is invoked, and using global variables would be quite dirty...