By DropSolutions on

Hi guys, like I said I need help with a PHP problem in a computed field. I'm a novice in PHP, but I do understand Drupal.

I've got 3 fields in a multifield. Two of them are numeric fields, the third one being computed.

Here is my code of my computed field:

$node_field[0]['value'] = $node->field_interim_weight[0]['value'] * $node->field_interim_score[0]['value'] / 5;
$node_field[1]['value'] = $node->field_interim_weight[1]['value'] * $node->field_interim_score[1]['value'] / 5;
$node_field[2]['value'] = $node->field_interim_weight[2]['value'] * $node->field_interim_score[2]['value'] / 5;

Everything works fine, but as you can make out, if ever I should add an extra multi-field, then my 4th field won't have a value.
Is there a variable I can use instead of inserting my delta values? Cause when I only have 1 value to insert, the rest shows zero.

I just want to know if I can make this process easier using PHP variables.

Any urgent help would be appreciated!

Thanx

⋅ Categories: Drupal 6.x

Comments

marcvangend’s picture

marcvangend
he/him
Primary language Dutch
Location Amsterdam
commented

Untested, but I think this should work:

foreach ($node->field_interim_weight as $key => $interim_weight) {
  if (isset($node->field_interim_score[$key]['value'])) {
    $node_field[$key]['value'] = $interim_weight['value'] * $node->field_interim_score[$key]['value'] / 5;
  }
}

[edit: fixed php typo in the isset-statement]