Using ImageField

Here is my scenario:

URL - http://www.integragroup.com/news/articles

Here is the code that generates that listing:

$taxo_id = 2;
$list_no =20;
$sql = "SELECT node.title, node.created, node.nid, content_field_excerpt.field_excerpt_value FROM node INNER JOIN term_node ON node.nid = term_node.nid INNER JOIN content_field_excerpt ON node.nid = content_field_excerpt.nid WHERE (term_node.tid = $taxo_id) ORDER BY node.created DESC LIMIT $list_no";
print "<table border='0' class='itemlisting'>";
$result = db_query($sql);
while ($anode = db_fetch_object($result)) { 

print l($anode->title, "node/".$anode->nid);

print l($anode->field_excerpt_value, "node/".$anode->nid);

}
print "</table>";

The goal is to have a thumbnail associated with each item in the listing. I have installed the imagefield module and added a image field called field_article_image_thumb to the news content type (those are news pages in the listing).
The field works fine...it uploads the file to the folder i specified successfully.

How do I now update the code above to not only pull node.created, node.nid, content_field_excerpt etc.. but also to include the image for each post?

I realize that the image is not stored in the db but the path to the image is. If i could even access the path and know how to print it that would work for me as well.

I realize how powerful drupal can be and as this is the first Drupal site i'm working on I want to learn the ropes rather than quit for an easier CMS...I think this is worth it.

Thanks you very much!