By tomas.teicher on

hi,
I have ajax script which call my own php script. In this script I want to use drupal standard functions. I want to avoid to use including for each php file I use. Is any standard way, how to use drupal functions (as t(), l() etc) in my php file called with ajax?
thanks for advise
Tomas

⋅ Categories: Drupal 6.x

Comments

suthagar’s picture

suthagar commented

go through this http://drupal.org/node/305747

tomas.teicher’s picture

tomas.teicher commented

thanks for your griff,
I have done everything according the tutorial. But it id not work for me.At least not at all.
I have problem with javascript function imageDetails or with response variable.

var imageDetails = function(response) {
  var result = Drupal.parseJson(response);
  $('.photo-container').html(result.data);
}

after I run ajax, my page is loading neverending. When I give this line to comment

//$('.photo-container').html(result.data);

I see result in my console in firebug, so I think result is ok?

I have very simple data in my function in my module 

drupal_json(array('status' =>  0, 'data' => 'hello'));
rkdeveloper’s picture

rkdeveloper commented

$('#photo-container').html(result.data);

change .photo-container to #photo-container and let me know if it solves your problem. we usually give div id appended with #before and render html in the div.

tomas.teicher’s picture

tomas.teicher commented

I created test div

<div id="test-ajax"></div>

I added it in page.tpl

then I used
$('#test-ajax').html(result.data);
Unfortunately, this does not work, too.

I have this js function:

var imageDetails = function(response) {
  console.log('my test log');
  var result = Drupal.parseJson(response);
  $('#test-ajax').html(result.data);
}

When I look in firebugconsole I see this:
(do not click on the links, it is only sample, how my output looks)

GET http://www.myweb.sk/mypath
my test log
GET http://www.myweb.sk/misc/jquery.js...
GET http://www.myweb.sk/misc/drupal.js...
..and so on. Output of all modules follows and then whole website disappear and blank page appears, but keeps loading neverending.
I do not know where is problem.

When I comment this line

//$('#test-ajax').html(result.data);

I see only this output in firebug console

GET http://www.myweb.sk/mypath
my test log

without loading whole site

tomas.teicher’s picture

tomas.teicher commented

I think I know where I made mistake but I cannot fix it. I have this sample code in mymodule.module file

/**
* Implementation of hook_menu().
*/
function mymodule_menu() {
  $items['photos/get/photos'] = array(
    'page callback' => 'mymodule_get_photos_ajax',
    'type' => MENU_CALLBACK,
    'access arguments' => array('access content'),
  );
  return $items;
}
 
function mymodule_get_photos_ajax($nid) {
  drupal_json(array('status' => 0, 'data' => 'data'));
}

but this code is never applied. I can comment whole code and nothing changed on my page. How do I force Drupal site to go through this code? I thought that I should go on page 'photos/get/photos', then I add click() function to some css selector on the site and it is done

Drupal.behaviors.mymodule = function() {
  $('#my_div', context).addClass('mymodule-processed')
  .bind('click', function(){
    $.get('/photos/get/photos, null, imageDetails);
    return false;
  });
}

Should I use another selector than "a" tag?