By khaki on

hello...

i have created a content-type the will accept some images (i'm using imagefield module)... then i created a "view block" (basing on the content type) that will accept some arguments... basically the views is working fine and display corresponding image if given correct argument... my question is how do i output the default image in views that is being define on the content-type if the argument is invalid?

thanks

khaki

⋅ Categories: Drupal 6.x

Comments

jghwork’s picture

jghwork commented

I think what you want to do is make a module or in your template.php a function that hooks the view_block function (of views module). Sorry I don't have the code for this

khaki’s picture

khaki commented

my drupal experience is not that good... i wish anyone or someone could share some idea...