How to render exposed filters in Views 3 programmatically?

Ok, the process is like this:

1. A JSON request is processed via JavaScript, i. e. $.getJSON(settings['dialog'], function(data, textStatus) ...
2. Then a custom menu call back is accessed
3. The view is rendered like
3.a $output = call_user_func_array('views_embed_view', $args); or
3.b $output = views_embed_view($view->name, $display_id);
4. The $output is returned as a JSON string:
$ret_msg['data'] = $output; drupal_json($ret_msg);
5. Finally on the client side the rendered html (data) is inserted in the DOM and processed further with jQuery UI

That's about it. For more details please have a look at this release especially at the files
- js/explorer.actions.js from line 38 - 56
- includes/nodereference_explorer.menu.inc, function nodereference_explorer_dialog()
- includes/nodereference_explorer.views.class.inc, function get_display()

Probably the View is generating this problem (see attachment). Nevertheless I am looking for a View which is compatible with the versions 2 & 3.

I detected the source of the problem. It's the way how exposed forms are included programmatically. Here's a working code from Views 2:

   $view = $this->view->clone_view();
    $view->set_display($display_id);
    $view->init_handlers(); //initialize display handlers
    $form_state = array(
      'view' => $view,
      'display' => $view->display_handler->display,
      'method' => 'get',
      'rerender' => TRUE,
      'no_redirect' => TRUE,
    );
    $form = drupal_build_form('views_exposed_form', $form_state); //create the filter form
    return $form;

However Views 3 requires a form plugin object in the $form_state array, i. e. $form_state['exposed_form_plugin'];

So my question is: Is the client responsible for creating this object or is rendering of forms done in a different way?

For my purposes it would be convenient to keep this code, as I don't see any advantage of creating a plugin object manually.

Thanks merlinofchaos, the solution is quite easy now. I just have to get the exposed form plugin from the view object. This code works for me in Views 2 & 3:

//create a view object first, e. g. $view = views_get_view('myViewName');
//then set the demanded display_id, e. g. $display_id = 'page_1';
$view->set_display($display_id);
$view->init_handlers(); //initialize display handlers
$form_state = array(
  'view' => $view,
  'display' => $view->display_handler->display,
  'exposed_form_plugin' => $view->display_handler->get_plugin('exposed_form'), //exposed form plugins are used in Views 3
  'method' => 'get',
  'rerender' => TRUE,
  'no_redirect' => TRUE,
);
$form = drupal_build_form('views_exposed_form', $form_state); //create the filter form
//you now have a form array which can be themed or further altered...