Making $node->type or similar available in page.tpl.php

The node object is exported to the page template. It is set up in the phptemplate_node() and not as apart of _phptemplate_callback().

You should be able to access it via the $node variable.
--
Gordon Heydon
Heydon Consulting

$node->type

Should be able to get the node type in your node.tpl.php. Then you should be able to create IF/ELSE statements that control it. For example:

if($node->type == "blog") {
print $title;
}

Of course you probably want to use it with the alternate syntax, as that is the method that phptemplate uses and allows for better html formatting. for example:

<?php if($node->type == "page"): ?>
<h2>$title</h2>
<?php endif ?>

I haven't actually tested it but use $node->type to output which type it is and add it to the nodes container for specific styling.

Hope that helps!

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erik mallinson

See http://drupal.org/node/11811 and apply it to theme_node, ie. make _phptemplate_node with appropriate parameters. You will get node and you may do whatever you wish here before the callback.

Am I right to say that $node is now available in page.tpl.php as of 4.7?

From an ecommerce perspective, I can also use $node->ptype (cool).

.s

Did something change in the latest release? (4.7.2)

All I did was add this to my body class=.. in the page.tpl.php file.

if ($node->type) { print "b-type-" . ($node->type); }

Prints out fine when the node is in full view and hides elsewhere.

–joon park
http://www.dvessel.com

Interestingly, in 4.6 I get inconsistent results when trying to reference $node->type in page.tpl.php: on some nodes I get it and on others I don't.

Here's the code I'm using to get the $tid for the current node in order to display a particular image:

/* get category tid for this page */
	if (arg(0)=='node') { 
	  /* lookup issue category given nid */
  	  if (strlen(arg(1)) <= 0) {
	  	$this_tid = NULL;
		} else
		{
			$ssql = db_rewrite_sql("SELECT DISTINCT td.tid FROM {term_data} AS td INNER JOIN {term_node} AS tn USING (tid) INNER JOIN {node} AS n WHERE td.vid=1 AND tn.nid=".arg(1)." AND n.type='flexinode-11';");
		  $result = db_query($ssql);
		  if($row = db_fetch_object($result)) {
		    $this_tid = $row->tid;  
		  } else {
		    $this_tid = NULL;	
	  	  }
		}
	} else {
		$this_tid = NULL;
	}
	$output = "";
	if ($this_tid != NULL) {

		/* display issue image without labels for this page's category */

	}
	print $output;

Joe Murray

Thanks for the snippet here, guys... great stuff...

http://drupal.org/node/17777#comment-32105

I used this because I was trying to turn off TinyMCE for particular node types, but I didn't know how to do it. But this helped me get things sorted.

Best,

Albert
Esalen Alumni Group

If you want the full node object available in page.tpl.php you can get it without exposing yourself to security issues or additional unnecessary database hits.

Insert the following at the top of node.tpl.php:

<?php
global $mynode;

if($page) {
  $mynode = $node;
}
?>

Then, in page.tpl.php:

<?php
global $mynode;

if($mynode != null)
{
  // Do some stuff with the node data.
}

?>

This simply creates a global handle on the node that has already been loaded and rendered by Drupal. You can access it similarly from anywhere in your template architecture... anywhere that is called after theme_node anyway...